Full access allows:
- Solve all tests online without limits;
- Remove all advertisements on website;
- Adding questions to favorite list;
- Save learning progress;
- Save results of practice exams;
- Watching all wrong answered questions.
- Homepage »
- Master & Chief Mate (Oceans or Near Coastal (Unlimited Tonnage)) »
- Q104 - Deck Safety: Stability Problems
115. In order to check your vessel's stability, a weight of 40 tons is lifted with the jumbo boom, the boom head being 50 feet from the ship's centerline. The clinometer is then carefully read and shows a list of 5°. The vessel's displacement is 8,000 tons including the suspended weight. What will be the metacentric height of the vessel at this time?
The metacentric height is calculated using the formula GM = (w x d) / (Δ x tan (θ)), where w is the weight, d is the horizontal distance, Δ is the displacement, and θ is the list angle. Substituting the given values yields a metacentric height of 2.86 feet.
Comments (0)
There are no comments at the moment. If you found an error or think question is incorrect, tell everyone about it
Only signed in users can write comments
Signin