150. On 21 April your 1542 zone time DR position is LAT 28°54.0'S, LONG 19°07.0'W. At that time, you observe the Sun bearing 299°psc. The chronometer reads 04h 44m 11s, and the chronometer error is 01m 54s fast. The variation is 3°E. What is the deviation of the standard compass?

The correct answer is 0.3W. This is determined by calculating the Sun's true bearing using sight reduction techniques and applying the formula T = C + d + v, where T is the true bearing, C is the compass bearing, d is the deviation, and v is the variation. Solving for deviation (d) yields a value of approximately 0.3W.