Full access allows:
- Solve all tests online without limits;
- Remove all advertisements on website;
- Adding questions to favorite list;
- Save learning progress;
- Save results of practice exams;
- Watching all wrong answered questions.
- Homepage »
- Master (Oceans or Near Coastal (Limited Tonnage: Less Than 500-1600 GRT)) »
- Q126 - Navigation Problems: Near Coastal
206. On 7 April in DR position LAT 27°42.0'N, LONG 114°03.0'W, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 076°psc. The chronometer reads 02h 10m 17s and is 01m 52s slow. Variation in the area is 8°E. What is the deviation of the standard magnetic compass?
The compass deviation is 1.8W because the observed compass bearing (076) exceeds the magnetic bearing (74.2) by that amount, consistent with the principles of variation and deviation.
Comments (0)
There are no comments at the moment. If you found an error or think question is incorrect, tell everyone about it
Only signed in users can write comments
Signin