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- Q127 - Navigation Problems: Oceans
57. On 11 May your vessel's 1839 ZT position is LAT 17°30'N, LONG 63°55'W, when an amplitude of the Sun's center is observed on the celestial horizon bearing 301° per standard magnetic compass. Variation for this area is 10.5°W. The chronometer reads 10h 37m 10s and is 02m 08s slow. What is the deviation of the compass?
The compass deviation is 1.5W, calculated by comparing the true azimuth (289T) derived from the amplitude with the observed 301 compass bearing and the 10.5W variation.
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