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- Q127 - Navigation Problems: Oceans
79. On 13 October your vessel's 1722 zone time DR position is LAT 27°36'S, LONG 136°16'E, when an amplitude of the Sun is observed. The Sun's center is on the celestial horizon and bears 266° per standard magnetic compass. Variation in the area is 2°W. The chronometer reads 08h 24m 19s and is 01m 43s fast. What is the deviation of the standard magnetic compass?
The observed Sun's bearing of 266M, after accounting for 2W variation, yields a true bearing of 263.2T. Calculating the true amplitude from the latitude and declination results in a true bearing of 261.2T, indicating a compass deviation of 2.8W.
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