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- Q134 - Navigation Problems: Near Coastal
160. At 2048 ZT on 13 October you are in DR position LAT 44° 02.8' S, LONG 146° 58.3' E, when you observe an amplitude of Venus. The planet is about one Sun's diameter above the visible horizon and bears 222.2° psc. The variation is 15° E. What is the deviation?
The deviation is 1.0 W because the compass bearing corrected for variation (222.2 + 15 = 237.2) is 1.0 greater than the true bearing calculated from the amplitude (236.2).
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