Full access allows:
- Solve all tests online without limits;
- Remove all advertisements on website;
- Adding questions to favorite list;
- Save learning progress;
- Save results of practice exams;
- Watching all wrong answered questions.
- Homepage »
- Master (Oceans or Near Coastal (Limited Tonnage: Less Than 500-1600 GRT)) »
- Q134 - Navigation Problems: Near Coastal
181. At 2326 ZT on 22 June, your vessel's position is LAT 28° 30' N, LONG 150° 04' W. An azimuth of the planet Jupiter is observed, and the standard compass bearing is 250.4°. The chronometer reads 09h 24m 36s and is 01m 12s slow. The variation of this area is 13.5° E. What is the deviation of the standard compass?
Deviation is 2.3E. The difference between the true azimuth (266.2) and the standard compass bearing (250.4), adjusted for variation (13.5E), determines the deviation.
Comments (0)
There are no comments at the moment. If you found an error or think question is incorrect, tell everyone about it
Only signed in users can write comments
Signin