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- Q135 - Navigation Problems: Oceans
162. At 1610 ZT on 14 August, in DR position LAT 33° 24.6' S, LONG 028° 15.4' W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon and bears 111.0° psc. The variation is 2° E. What is the deviation?
The deviation is calculated using the formula T = C + D + V, where T is the true bearing, C is the compass bearing, and V is the variation. Given C = 111.0, T ≈ 111.9, and V = 2 E, solving for D yields a deviation of 1.1 W.
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