Full access allows:
- Solve all tests online without limits;
- Remove all advertisements on website;
- Adding questions to favorite list;
- Save learning progress;
- Save results of practice exams;
- Watching all wrong answered questions.
- Homepage »
- Master (Oceans or Near Coastal (Limited Tonnage: Less Than 500-1600 GRT)) »
- Q135 - Navigation Problems: Oceans
295. On 26 May your 0723 zone time DR position is LAT 24°50.0'N, LONG 38°11.0'W. At that time, you observe the Sun bearing 076.5°psc. The chronometer reads 10h 25m 43s, and the chronometer error is 02m 57s fast. The variation is 7°W. What is the deviation of the standard magnetic compass?
The deviation of the standard magnetic compass is calculated by subtracting the observed compass bearing from the true azimuth, then accounting for the variation. The correct deviation is 10.7E, determined by applying the formula True = Compass + Variation + Deviation and solving for the deviation.
Comments (0)
There are no comments at the moment. If you found an error or think question is incorrect, tell everyone about it
Only signed in users can write comments
Signin